If α,β are the roots of the equation ax2 +2bx +c = 0 and α+δ, β+δ are the roots of Ax2 + 2Bx + C= 0 , then b2–acB2–AC =
(a / A)2
α,β are the roots of the equation ax2+2bx+c = 0 => |α−β |= √b2−ac|a|
α+δ, β+δ are the roots of Ax2+2Bx+C= 0 => |α+δ - β+δ| =√b2−4ac|a|
b2–aca2 = B2–ACA2 => b2–acB2AC= a2A2