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Question

If α,β are the roots of the equation ax2 +2bx +c = 0 and α+δ, β+δ are the roots of Ax2 + 2Bx + C= 0 , then b2acB2AC =


A

a / A

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B

A / a

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C

(a / A)2

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D

(A / a)2

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Solution

The correct option is C

(a / A)2


α,β are the roots of the equation ax2+2bx+c = 0 => |αβ |= b2ac|a|

α+δ, β+δ are the roots of Ax2+2Bx+C= 0 => |α+δ - β+δ| =b24ac|a|

b2aca2 = B2ACA2 => b2acB2AC= a2A2


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