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Question

If α,β are the roots of the equation ax2+bx+c=0 and Sn=αn+βn then aSn+1+bSn+cSn1=(n2)


A

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B

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C

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D

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Solution

The correct option is A


Sn+1=αn+1+βn+1=(α+β)(αn+βn)αβ(an1+βn1)=ba.Snca.Sn1


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