If α,β are the roots of the equation x2+x+3=0, then the equation 3x2+5x+3=0 has root
A
αβ
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B
βα
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C
αβ+βα
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D
none of these
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Solution
The correct options are Aαβ Bβα Considering x2+x+3=0 α+β=−1 And α.β=3 Now α2+β2=1−2(3) =−5 Hence, α2+β2α.β=αβ+βα=−53 Let αβ=α′ and βα=β′ Hence, (x−α′)(x−β′)=0 be a quadratic equation. x2−(α′+β′)+α′.β′=0 Substituting the value of roots we get x2−−5x3+1=0 3x2+5x+3=0