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Question

If α,β are the roots of the equation lx2+mx+n=0, find the equation whose roots are αβ,βα

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Solution

Given that α,β are roots of equation lx2+mx+n=0
So we have α+β=ml and αβ=nl
Let us consider x2+ax+b=0 be our required equation whose roots are αβ,βα
Sum of roots is a=αβ+βα=α2+β2αβ=(α+β)22αβαβ=m22nlnl
a=(m22nlnl)
Product of roots is b=αβ×βα=1
Therefore the required equation is x2(m22nlnl)x+1=0
nlx2(m22nl)x+nl=0

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