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Question

If α,β are the roots of the equation x2+px+q=0, find the value of α3β+αβ3.

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Solution

α and β one roots of x2+px+q=0

α+β=p and αβ=q

We have to find α3β+αβ3
(αβ)(α2+β3)
α2+β2=(α+β)22αβ
=(p)22(q)=p22q
(αβ)(α2+β2)=q(p22q)
p2q2q2
α3β+αβ3=p2q2q2

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