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Question

if α,β are the roots of the equation x2x+1=0, then α2009+β2009 =

A
-1
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B
1
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C
2
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D
-2
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Solution

The correct option is B 1
x2x+1=0x=1±142x=1±3i2α=12+i32=ω2β=12i32=ωα2009+β2009=(ω2)2009+(ω)2009=ω2ω=1

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