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Question

If α,β are the roots of x2(a2)x(a+1)=0 where a is a variable, then the least value of α2+β2 is

A
2
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B
43
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C
5
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D
7
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Solution

The correct option is C 5
α2+β2=(α+β)22αβ
=(a2)2+2(a+1)
=a24a+4+2a+2
=a22a+6
=(a1)2+5
Minimum value is at a=1.
Value of expression at a=1 is 5.

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