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Question

If α,β are the roots of x2(k+1)x+12(k2+k+1)=0, then show that α2+β2=k.

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Solution

α2+β2=(α+β)22αβ
=(k+1)22×12(k2+k+1)
since
α+β=ba=k+1;αβ=ca=12(k2+k+1)
=k2+2k+1k2k1
α2+β2=k

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