If - - are the roots of x2-px-1-C-0- then -1-1-

The correct option is B 1+Cx^2 p(x+1)+C x^2 px p+C α+ β =p/1 αβ= p+C Now, (α+1)(β+1) =αβ+α+β+1 = p+C+p+1 =C+1 ...

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If α, β are t...

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If $α, β$ are the roots of $x^{2} - p (x + 1) + C = 0$ , then $(α + 1) (β + 1)$ =

1- C

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1+C

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C-1

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If $α, β$ are roots of the equation $x^{2} - p (x + 1) - c = 0$ , then

$(α + 1) (β + 1)$ =

x^{2} - p (x + 1) - c = 0, then (α + 1) (β + 1) =

α, β

f (x) = x^{2} - p (x + 1) - c = 0

(α + 1) (β + 1) = 0

c =

α, β

x^{2} - p (x + 1) - c = 0

(α + 1) (β + 1) = 1 - c

\frac{α^{2} + 2 α + 1}{α^{2} + 2 α + c} + \frac{β^{2} + 2 β + 1}{β^{2} + 2 β + c} = 1

If α and β are the roots of the equation $x^{2} - a (x + 1) - b = 0$ , then $(α + 1) (β + 1) =$

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