If - are the roots of x2-px-q-0 and - - are the roots of x2-px-r-0- then the value of - is

Α,β are the roots of x^2+px q=0 Sum of the roots, α+β= p nbsp; γ, δ are the roots of x^2+px+r=0 Sum of the roots, γ+δ= p Now, α+β = γ+δ ⇒α γ=δ β⋯(1) ⇒α ...

406

You visited us 406 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Mathematics

Relations Between Roots and Coefficients

If α,β are th...

Question

If $α, β$ are the roots of $x^{2} + p x - q = 0$ and $γ, δ$ are the roots of $x^{2} + p x + r = 0$ , then the value of $\frac{(α - γ) (α - δ)}{(β - γ) (β - δ)}$ is

1.0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.00

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

$α, β$ are the roots of $x^{2} + p x - q = 0$
Sum of the roots,
$α + β = - p$

$γ, δ$ are the roots of $x^{2} + p x + r = 0$
Sum of the roots,
$γ + δ = - p$

Now,
$α + β = γ + δ$
$\Rightarrow α - γ = δ - β \dots (1) \Rightarrow α - δ = γ - β \dots (2)$

Using equation $(1)$ and $(2)$ ,
$\frac{(α - γ) (α - δ)}{(β - γ) (β - δ)} = \frac{(δ - β) (γ - β)}{(β - γ) (β - δ)} = 1$

Suggest Corrections

Similar questions

Q. If α, β are the roots of the equation

x^{2} + p x + 1 = 0; γ, δ

the roots of the equation

x^{2} + q x + 1 = 0, t h e n (α - γ) (α + δ) (β - γ) (β + δ) =

(a)

q^{2} - p^{2}

(b)

p^{2} - q^{2}

(c)

p^{2} + q^{2}

(d) none of these.

Q. If

α, β

are the roots of

x^{2} + p x - q = 0

and

γ, δ

are the roots of

x^{2} + p x + r = 0

, then the value of

\frac{(α - γ) (α - δ)}{(β - γ) (β - δ)}

Q. If

α, β

be the roots

x^{2} + p x - q = 0

and

γ, δ

be the roots of

x^{2} + p x + r = 0

, then

\frac{(α - γ) (α - δ)}{(β - γ) (β - δ)} =

Q. lf

α, β

are the roots of

x^{2} + p x - q = 0

and

γ, δ

that of

x^{2} + p x + r = 0

, then

(α - γ) (β - γ) (α - δ) (β - δ) =

Q. If

α, β

are roots of the equation

x^{2} + p x - q = 0

and

γ, δ

are roots of

x^{2} + p x + r = 0,

then the value of

(α - γ) (α - δ)

is-

Join BYJU'S Learning Program

If α,β are the roots of x2+px−q=0 and γ,δ are the roots of x2+px+r=0, then the value of (α−γ)(α−δ)(β−γ)(β−δ) is

α,β are the roots of x2+px−q=0 Sum of the roots, α+β=−p γ,δ are the roots of x2+px+r=0 Sum of the roots, γ+δ=−p Now, α+β=γ+δ ⇒α−γ=δ−β⋯(1)⇒α−δ=γ−β⋯(2) Using equation (1) and (2), (α−γ)(α−δ)(β−γ)(β−δ)=(δ−β)(γ−β)(β−γ)(β−δ)=1

If $α, β$ are the roots of $x^{2} + p x - q = 0$ and $γ, δ$ are the roots of $x^{2} + p x + r = 0$ , then the value of $\frac{(α - γ) (α - δ)}{(β - γ) (β - δ)}$ is