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Question
If α,β are the zeroes of polynomial f(x)=x2−p(x+1)−c, then (α+1)(β+1)=
If α,β are the zeroes of polynomial f(x)=x2−p(x+1)−c, then (α+1)(β+1)=
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Solution
The correct option is A 1-c
f(x)=x2−px−p−c
α+β=+p
αβ=−p−c
(α+1)(β+1)=αβ+α+β+1
=1−c
f(x)=x2−px−p−c
α+β=+p
αβ=−p−c
(α+1)(β+1)=αβ+α+β+1
=1−c
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