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Question

If α,β are the zeroes of the polynomial f(x)=ax2+bx+c, then find 1α+1β2αβ

A
b+2ac2a
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B
(ba+cab)
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C
(bc+2ca)
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D
(bc+ab)
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Solution

The correct option is A (bc+2ca)
Given, α,β are the zeroes of the polynomial f(x)=ax2+bx+c
α+β=ba
αβ=ca
Now, 1α+1β2αβ=β+αβα2αβ
=baca2ca
=bc2ca
=(bc+2ca)
Option C is correct.

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