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Question

If α,β are the zeros of the polynomial p(x)=2x27x+3 , then find the value of α2+β2.

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Solution

2x27x+3=P(x)
2x27x+3=0 Roots are α,β
α+β=72
αβ=32
α2+β2=(α+β)22αβ=(72)22(32)=4943=374

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