if alpha & beta are the zeros of the polynomial X square + 7 x + 12 find the values of one upon alpha + one upon beta + 2alpha beta

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Solution

$H i, x^{2} + 7 x + 12 = 0 α + β = \frac{- b}{a} = - 7 a n d α β = \frac{c}{a} = 12 s o h e r e \frac{1}{α} + \frac{1}{β} + 2 α β = \frac{α + β}{α β} + 2 α β = \frac{- 7}{12} + 24 = \frac{281}{12}$

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if alpha & beta are the zeros of the polynomial X square + 7 x + 12 find the values of one upon alpha + one upon beta + 2alpha beta

Hi, x2+7x+12= 0 α+β=-ba= -7 and αβ= ca= 12so here 1α+1β+2αβ=α+βαβ+2αβ=-712+24= 28112

$H i, x^{2} + 7 x + 12 = 0 α + β = \frac{- b}{a} = - 7 a n d α β = \frac{c}{a} = 12 s o h e r e \frac{1}{α} + \frac{1}{β} + 2 α β = \frac{α + β}{α β} + 2 α β = \frac{- 7}{12} + 24 = \frac{281}{12}$