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Byju's Answer
Standard XII
Mathematics
Theorems for Differentiability
If α, β are...
Question
If
α
,
β
are zeros of
x
2
+
5
x
+
5
, find the value of
α
−
1
+
β
−
1
A
-1
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B
1
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C
0
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D
2
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Solution
The correct option is
A
-1
f
(
x
)
=
x
2
+
5
x
+
5
a
=
1
,
b
=
5
,
c
=
5
So,
α
+
β
=
−
b
a
=
−
5
and
α
β
=
c
a
=
5
value of
α
−
1
+
β
−
1
=
1
α
+
1
β
=
β
+
α
α
β
=
−
5
5
So,
α
−
1
+
β
−
1
=
−
1
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8
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