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Question

If α,β be the real roots of the equation x2+ax+1=0.Then the minimum value of α2+β2 is

A
1
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B
4
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C
0
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D
2
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Solution

The correct option is D 2
α+β=a,α×β=1
α2+β2=(α+β)22αβα2+β2=a22
As the roots are real.
So, a240
a24
So minimum value of α2+β2=42=2

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