If -2 and - then tan- equals-

The correct option is C tanβ +2tanγ α+β=π2β=π2 α β+γ=αγ=2α π2 tanβ+2tanγ=tan(π2 α)+2tan(2α π2)=1tanα 21 tan^2α2tanα=tan^2αtanα=tanα ...

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A.M Greater than or Equal to G.M

If α+β=π2 a...

Question

If $α + β = \frac{π}{2}$ and $β + γ = α$ , then $tan α$ equals-

2 (tan β + tan γ)

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tan β + tan γ

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tan β + 2 tan γ

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2 tan β + tan γ

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I f α + β = \frac{π}{2} a n d β + γ = α, t h e n t a n α e q u a l s

tan β = \frac{2 sin α sin γ}{sin (α + γ)}

tan α, tan β, tan γ

α \neq 0 a n d γ \neq 0 a n d β \neq \frac{π}{2}

tan β = \frac{2 sin α sin γ}{sin (α + γ)}

tan α, tan β, tan γ

α \neq 0 a n d γ \neq 0 a n d β \neq \frac{π}{2}

x^{2} + y^{2} + z^{2} = r^{2}

tan α = \frac{x y}{z r}, tan β = \frac{y z}{x r}, tan γ = \frac{Z X}{y r}

α + β + γ =

tan α + tan β + tan γ - tan α tan β tan γ = \frac{sin (α + β + γ)}{cos α cos β cos γ}

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