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Question

If α+β+γ=2θ, then cosθ+cos(θα)+cos(θβ)+cos(θγ) then is equal to


A

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B

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C

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D

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Solution

The correct option is B


cos(θα)+cos(θβ)+cosθ+cos(θγ)
=2cos(θ(α+β2)) cos(βγ2)+2cos(γ2)cos(θγ2)
=2cos(γ2)cos(βα2) 2cos(γ2)+cos(α+β2)
=2cos(γ2)[cos(βα2) +cos(α+β2)]
=2cos(γ2) 2cosγ2cosβ2
4cosα2cosβ2cosγ2


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