If α,β,γ are roots of the equation x3+ax2+bx+c=0, thenα−1+β−1+γ−1=
−bc
ac
ca
ba
α,β,γ are the roots of the equation
x3+ax2+bx+c=0 so α+β+γ=−a, αβ+βγ+γα=b and αβγ=−c now α−1+β−1+γ−1=1α+1β+1γ=αβ+βγ+γααβγ=−bc
If α,β,γ are roots equation x3+ax2+bx+c=0, then α−1+β−1+γ−1=