If α,β,γ are the roots of px3+qx2+r=0, then the value of the determinant ∣∣
∣
∣∣αββγγαβγγααβγααββγ∣∣
∣
∣∣ is
A
p
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B
q
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C
0
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D
r
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Solution
The correct option is C0 Operation C1→C1+C2+C3 gives (αβ+βγ+γα)∣∣
∣
∣∣1βγγα1γααβ1αββγ∣∣
∣
∣∣
From the given equation, αβ+βγ+γα=0.
So, the value of determinant is 0