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Question

If α, β, γ are the roots of the equation x3px2+qx+r=0 then (α+β)(β+γ)(γ+α)=

A
2(p23q)
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B
rpq
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C
qp+r
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D
p22qr2
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Solution

The correct option is C qp+r
x3px2+qx+r=0
Roots are α,β,γ
α+β+γ=p
αβ+βγ+γα=q
αβγ=r
(α+β)(β+α)(γ+α)=(αβ+β2+αγ+βγ)(γ+α)
αβγ+β2γ+αγ2+βγ2+α2β+β2α+α2γ+αβγ
=(α2β+α2γ+αβγ)+(β2γ+β2α+αβγ)+(γ2α+γ2β+αβγ)αβγ
=α(αβ+βγ+γα)+β(αβ+βγ+γα)+γ(αβ+βγ+γα)αβγ
=(α+β+γ)(αβ+βγ+γα)αβγ
=pq+r

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