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Question

If α,β,γ are the roots of the equation x3+px2+qx+r=0 then the coefficient of x in the cubic equation whose roots are α(β+γ),β(γ+α) and γ(α+β) is

A
2q
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B
q2+pr
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C
p2qr
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D
r(pqr)
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Solution

The correct option is D q2+pr
The general equation from roots is
(xx1)(xx2)(xx3)=0
=x3(α+β+γ)x2+(αβ+βγ+γα)xαβγ=0

therefore p=(α+β+γ) and q=αβ+βγ+γα

r=αβγ

therefore the second equation is

x3x2(α(β+γ)+β(γ+α)+γ(α+β))+x(αβ(β+γ)(γ+α)+βγ(γ+α)(α+β)+αγ(α+β)(β+γ)αβγ(α+β)(β+γ)(γ+α)=0

therefore arranging the coefficient of x
α2β2+β2γ2+α2γ2+3αβγ(α+β+γ).....................(i)

q2=α2β2+β2γ2+γ2α2+2αβγ(α+β+γ)

the expression (i) can be written as

q2+αβγ(α+β+γ)

=q2+pr



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