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Question

If α,β,γ are the roots of x33x+7=0, then the equation whose roots are α+βγ,β+γα,γ+αβ is

A
x3+12x+56=0
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B
x312x56=0
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C
x3+12x56=0
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D
x312x+56=0
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Solution

The correct option is B x312x56=0
x33x+7=0 roots are α,β,γ
α+β+γ=0α+βγ=2γ,β+γα=2α,γ+αβ=2β

The required equation whose roots are 2α,2β,2γ is
f(x2)=0(x2)33(x2)+7=0x312x56=0

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