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Question

If α,β,γ are the roots of x3+px2+qx+r=0, then Σα3β3=

A
q3+3pqr+3r3
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B
q33pqr+3r3
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C
q3+3pqr+3r2
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D
q33pqr+3r2
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Solution

The correct option is D q33pqr+3r2
Given expression is x3+px2+qx+r=0
α+β+γ=pαβ+βγ+γα=qαβγ=r(αβ+βγ+γα)3=q3(αβ+βγ)3+(αγ)3+3(αβ+βγ)(αγ)(αβ+βγ+γα)=q3α3β3+3αβ2γ(αβ+βγ)+3q(r)(α+γ)=q3α3β33rβ(qαγ)3qr(pβ)=q3α3β3+3pqr3qrβ+3r(αβγ)+3qrβ=q3α3β3+3pqr3r2=q3α3β3=q33pqr+3r2

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