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Question

If α,β,γ are the roots of x3+qx+r=0 then1α+βγ+1β+γα+1γ+αβ=

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Solution

Form the given equation ,we can
see clearly that α+β+γ=0

Also we have αβ+βγ+γα=q
and αβγ=r

1α+β+γ+1β+γα+1γ+αβ

1α+β+γ2γ+1β+γ+α2α+1γ+α+β2β

=12(1α+1β+1γ)

=12(αβ+βγ+γααβγ)

12(qr)=q2r

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