If - - - - are in arithmetic progression-Then sin - is equal to

The correct options are A sin(3β+δ) B sin (α+3γ) As α ,β #10;,γ ,δ is in A.P #10;Let the common difference is r #10;Then, β =α +r,γ ...

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Cos(A+B)Cos(A-B)

If α, β, γ,...

Question

If $α, β, γ, δ$ are in arithmetic progression.Then $sin (α + β + γ + δ)$ is equal to

sin (3 β + δ)

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sin (α + 3 γ)

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sin (α + 3 δ)

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sin (3 β + γ)

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α, β, γ, δ

cos β

c o s α + c o s β + c o s γ = s i n α + s i n β + s i n γ = 0

s i n 3 α + s i n 3 β + s i n 3 γ = 3 s i n (α + β + γ) .

cos α + cos β + cos γ = 0 = sin α + sin β + sin γ

cos 3 α + cos 3 β + cos 3 γ = 3 cos (α + β + γ)

sin 3 α + sin 3 β + sin 3 γ = 3 sin (α + β + γ)

0 < α, β, γ < π / 2

sin α + sin β + sin γ > sin (α + β + γ)

β = \frac{2 sin α sin γ}{sin (α + γ)},

cot α, cot β, cot γ

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