If - - - - are in arithmetic progression-Then sin - is equal to

The correct options are A sin(3β+δ) B sin (α+3γ) As α ,β #10;,γ ,δ is in A.P #10;Let the common difference is r #10;Then, β =α +r,γ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Cos(A+B)Cos(A-B)

If α, β, γ,...

Question

If $α, β, γ, δ$ are in arithmetic progression.Then $sin (α + β + γ + δ)$ is equal to

sin (3 β + δ)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

sin (α + 3 γ)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

sin (α + 3 δ)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

sin (3 β + γ)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

α, β, γ, δ

cos β

c o s α + c o s β + c o s γ = s i n α + s i n β + s i n γ = 0

s i n 3 α + s i n 3 β + s i n 3 γ = 3 s i n (α + β + γ) .

cos α + cos β + cos γ = 0 = sin α + sin β + sin γ

cos 3 α + cos 3 β + cos 3 γ = 3 cos (α + β + γ)

sin 3 α + sin 3 β + sin 3 γ = 3 sin (α + β + γ)

0 < α, β, γ < π / 2

sin α + sin β + sin γ > sin (α + β + γ)

β = \frac{2 sin α sin γ}{sin (α + γ)},

cot α, cot β, cot γ

Join BYJU'S Learning Program