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Question

If α,βI+ are the roots of the equation x2+ax+b=0, where a=iπ×lni and bR, then the number of possible pairs of (α,β) is/are 
  1. 0
  2. 1
  3. 2
  4. 4


Solution

The correct option is A 0
x2+ax+b=0
α+β=a1=a
a=iπ×lni
=iπ×lneiπ2=12 
α+β=a=12 which is not possible. 

Note: the answer will be same if you take  i=ei(2n+1)π2

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