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Question

If α,βR are such that 12i (here i2=1) is a root of z2+αz+β=0, then (αβ) is equal to

A
7
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B
3
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C
3
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D
7
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Solution

The correct option is D 7
12i is a root of z2+αz+β=0.
So, (12i)2+α(12i)+β=0
144i+α2iα+β=0
(α+β3)i(4+2α)=0
α+β3=0 and 4+2α=0
So, α=2,β=5
αβ=7

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