If (α,β), (¯x,¯y)and(u,v)are respectively coordinates of the circumcentre, centroid and orthocentre of a triangle.
A
3¯x=2α+uand3¯y=2β+v
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B
3¯x=2α−uand3¯y=2β−v
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C
3¯x=2α−uand3¯y=2β+v
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D
3¯x=2α+uand3¯y=2β−v
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Solution
The correct option is C 3¯x=2α−uand3¯y=2β+v We know that, the centroid of a triangle divides the segment joining the orthocentre and circumcentre internally in the ratio 2 : 1. Therefore, ¯x=2α+u2+1and¯y=2β+v2+1 ⇒3¯x=2α+uand¯y=2β+v