If $α_{c}$ and $α_{f}$ denote the numerical values of coefficient of linear expansion of a solid, expressed per $^{0} C$ and per $^{0} F$ respectively, then:

α_{c} > α_{f}

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α_{f} > α_{c}

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α_{f} = α_{c}

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α_{f} + α_{c} = 0

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Solution

The correct option is A $α_{c} > α_{f}$
$α = \frac{c h a n g e i n l e n g t h}{(o r i g i n a l l e n g t h) \times (c h a n g e i n t e m p e r a t u r e)}$
Now, in centigrade scale, the change of temperature will be less than that of in Fahrenheit scale. For a change of 5 degree in centigrade scale there is a change of 9 degree in Fahrenheit scale. So, coefficient of linear expansion of a solid, expressed centigrade scale will be more than that of Fahrenheit scale.

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If αc and αf denote the numerical values of coefficient of linear expansion of a solid, expressed per 0C and per 0F respectively, then:

If $α_{c}$ and $α_{f}$ denote the numerical values of coefficient of linear expansion of a solid, expressed per $^{0} C$ and per $^{0} F$ respectively, then: