Question

If $\alpha ϵ(-1,1)$ then roots of the quadratic equation $(a-1)x^2+ax+\sqrt{1-a^2}=0$ are

• A. real
• B. imaginary
• C. both equal
• D. none of these

Answer 1

The correct option is A real

Given,

$(a-1)x^2+ax+\sqrt{1-a^2}=0$

$x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-a\pm \sqrt{a^2-4(a-1)\sqrt{1-a^2}}}{2(a-1)};a\ne 1$

Hence the roots of quadratic equation.