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Question

If α is a repeated root of ax2+bx+c=0 then limxαsin(ax2+bx+c)(xα)2 is

A
0
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B
a
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C
b
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D
c
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Solution

The correct option is B a
limxαsin(ax2+bx+c)(xα)2=limxαsina(xα)(xα)(xα)2
=limxαsina(xα)2a(xα)2×a=a

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