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Question

If α= mC2, then find the value of αC2.

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Solution

We have α= mC2=m(m1)2

( nCr=n!r!(nr)!)
Now αC2=α(α1)2
=(m(m1)2)(m(m1)21)2=m(m1)(m2m2)2×2×2=m(m1)(m+1)(m2)8=m(m1)(m+1)(m2)4×2
Multiplying with 3, numerator and denominator to make 4
Or =m(m+1)m(m1)(m2)4.3.2.1
=3(m+1)m(m1)(m2)4!
=3.m+1C4(nCr=n!r!(nr)!)


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