If α→a+β→b+γ→c=→0, then the resultant of (→a×→b)×{(→b×→c)×(→c×→a)} is
(where α,β and γ are not simultaneously zero.)
A
α−β+γ
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B
(α+β+γ)(→a+→b+→c)
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C
γ→a+→b
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D
→0
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Solution
The correct option is D→0 As α→a+β→b+γ→c=→0
Therefore, the vectors →a,→b,→c are coplanar. ⇒→b×→c and →c×→a are parallel ⇒(→b×→c)×(→c×→a)=→0
Hence, (→a×→b)×{(→b×→c)×(→c×→a)} =(→a×→b)×{→0}=→0