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Question

If α+β+γ=2π, then


A

tanα2+tanβ2+tanγ2=tanα2tanβ2tanγ2

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B

tanα2tanβ2+tanβ2tanγ2+tanγ2tanα2=1

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C

tanα2+tanβ2+tanγ2=-tanα2tanβ2tanγ2

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D

None of these

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Solution

The correct option is A

tanα2+tanβ2+tanγ2=tanα2tanβ2tanγ2


Explanation for the correct option:

Given, α+β+γ=2π

(α+β+γ)2=π

Take “tan” on both sides,

tanα2+β2+γ2=tanπ

tanα2+tanβ2+tanγ2tanα2tanβ2tanγ21tanα2tanβ2tanβ2tanγ2tanγ2tanα2=0

tanα2+tanβ2+tanγ2tanα2tanβ2tanγ2=0

tanα2+tanβ2+tanγ2=tanα2tanβ2tanγ2

Hence, Option ‘A’ is Correct.


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