wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If α and β are the zeroes of p(x)=4x2+10x+k such that α2+β2+αβ=214, then k =

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
- 12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4
Given, α and β are zeroes of a polynomial.
α+β=104and αβ=k4

Now, it is given that
α2+β2+αβ=214 (α+β)22αβ+αβ=214 (104)2αβ=214 (104)2k4=214 10016k4=214
1004k16=214 1004k=84 10084=4k k=4

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relationship between Zeroes and Coefficients of a Polynomial
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon