If AM and GM of two positive numbers a and b are 10 and 8 respectively, find the numbers.
AM = 10
∴a+b2=10
⇒a+b=20 ......... (i)
Also, G = 8
∴√ab=8
⇒ab=82
⇒ab=64 ............(ii)
Using (i) and (ii);
⇒a(20−a)=64
⇒a2−20a+64=0
⇒a2−16a−4a+64=0
⇒a(a−16)−4(a−16)=0
⇒(a−16)(a−4)=0
⇒a=4,16
If a = 4, then b = 16
And, if a = 16, then b = 4