If AM is a median of triangle ABC, then which of the following relation will always hold good?

AB + BC + CA = 2AM

No worries! We‘ve got your back. Try BYJU‘S free classes today!

AB + BC + CA $>$ 2AM

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

AB + BC + CA $<$ 2AM

No worries! We‘ve got your back. Try BYJU‘S free classes today!

AB + BC + CA = AM

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
AB + BC + CA $>$ 2AM

Sum of lengths of any two sides of a triangle is always greater than the third side.
Hence,
AB + BM $>$ AM
AC + CM $>$ AM
Thus, AB + BC + CA $>$ 2AM

Suggest Corrections

Similar questions

AM is a median of $△ A B C$ . Then which of the following relation will always hold good?

If AM is a median of triangle ABC. Then AB +BC +CA $>$ 2AM

If $A M$ is median of $A B C$ . Prove that $(A B + B C + C A) > 2 A M$ .

A a circle with centre O has a radius of 3.5 cm. If the distance between a point P and the centre O is 5 cm, then P lies ___ of the circle.

A M

A B C

A B + B C + C A > 2 A M

Δ A B M a n d Δ A M C

Join BYJU'S Learning Program