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Question

If AM is a median of triangle ABC, then which of the following relation will always hold good?


A

AB + BC + CA = 2AM

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B

AB + BC + CA > 2AM

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C

AB + BC + CA < 2AM

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D

AB + BC + CA = AM

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Solution

The correct option is B

AB + BC + CA > 2AM



Sum of lengths of any two sides of a triangle is always greater than the third side.
Hence,
AB + BM > AM
AC + CM > AM
Thus, AB + BC + CA > 2AM


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