If AM is a median of triangle ABC, then which of the following relation will always hold good?

AB + BC + CA = 2AM

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AB + BC + CA $>$ 2AM

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AB + BC + CA $<$ 2AM

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AB + BC + CA = AM

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Solution

The correct option is B
AB + BC + CA $>$ 2AM

Sum of lengths of any two sides of a triangle is always greater than the third side.
Hence,
AB + BM $>$ AM
AC + CM $>$ AM
Thus, AB + BC + CA $>$ 2AM

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