If ammonia is added to pure water, the concentration of a chemical species already present will decrease. The species is:

O_{2}^{⊝}

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⊝ O H

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H_{3} O^{\oplus}

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H_{2} O

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Solution

The correct option is D $H_{3} O^{\oplus}$
$N H_{3} + H_{3} O^{+} \to N H_{4}^{+} + H_{2} O$
lewis base lewis acid
Here, ammonia will act as a base and hence, concentration of an acid $(H_{3} O^{+})$ will decrease.

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Similar questions

Q. In a

0.1 M

solution of

H_{3} P O_{4}

the ionic species present are (besides

H_{3} O^{+}

and

O H^{-}

Q. The concentration of

H_{3} O^{+}

ions in pure water is

10^{- 6} m o l {d m}^{- 3}

. The corresponding concentration of

{O H}^{-}

ions will be:

Q. The correct decreasing order of basic strength of the following species is:

H_{2} O, N H_{3}, O H^{-}, N H_{2}^{-}

For a system in equilibrium, if the concentration of the reacting species is increased then the system will readjust itself to decrease the reactant concentration favoring a backward reaction.

Q. At what concentration of

[O H^{-}]

does the following half reaction has a potential of

0 V

when other species are at

1 M

N O_{3}^{-} + H_{2} O + 2 e^{-} \to N O_{2}^{-} + 2 O H^{-}; E^{0} c e l l = - 0.06 V

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If ammonia is added to pure water, the concentration of a chemical species already present will decrease. The species is:

The correct option is D H3O⊕NH3+H3O+→NH+4+H2O lewis base lewis acidHere, ammonia will act as a base and hence, concentration of an acid (H3O+) will decrease.

The correct option is D $H_{3} O^{\oplus}$
$N H_{3} + H_{3} O^{+} \to N H_{4}^{+} + H_{2} O$
lewis base lewis acid
Here, ammonia will act as a base and hence, concentration of an acid $(H_{3} O^{+})$ will decrease.