Question

If amount of heat supplied is Q, work done is W and change in internal energy is $m{C}_{V}dT$, then relation among them is $(C_V$ gram specific heat)

• A. $m{C}_{V}dT=Q+W$
• B. $Q=W+m{C}_{V}dT$
• C. $Q+m{C}_{V}dT=W$
• D. None of these

Answer 1

The correct option is B $Q=W+m{C}_{V}dT$

Given,

Heat supplied$=Q$

Work done $=W$

and change in internal energy $mCvdT$

$A/Q$ to first law of thermodynamics,

Change in internal energy, $dv=dQ-dW.......\left(i\right)$

putting the above values in equation $\left(i\right)$ we get,

$mCvdT=Q-W$

or $Q=W+mCvdT$

Hence, Option $B$ is correct.