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Question

If an air bubble of the same dimensions were formed at a depth of 30 cm inside a container containing the soap solution of relative density 1.20, then the pressure inside the bubble is (Take 1 atm = 1.01×105 Pa)

A
1.01×104 Pa
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B
1.05×105 Pa
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C
2.01×104 Pa
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D
3.01×104 Pa
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Solution

The correct option is B 1.05×105 Pa
Here, h=30cm=30×102m,
P0=1.01×105Pa
ρsoap=1.2×103kgm3
Excess pressure inside the air bubble,

P=2Sr=2×2.5×1026×103=8.3Pa

Pressure inside the air bubble at depth h in soap solution

P=P0+hρg

=8.3+1.01×105+30×102×1.2×103×9.8

=1.05×105Pa

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