If an air bubble rises from the bottom of a mercury tank to the top its volume become 112times. When normal pressure is 76 cm of Hg then the depth of the Hg tank is
A
38 cm
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B
132 cm
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C
76 cm
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D
49 cm
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Solution
The correct option is A 38 cm let the height be h pressure at the bottom = h + 76 (atmospheric pressure) now as it reaches at the top, pressure = 76 (only atmospheric pressure now) at constant temperature we can apply Boyle's law here P1 = h + 76 P2 = 76 V2=32V1 so by Boyle's law, we get P1V1=P2V2 on solving this gives h = 38 cm