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Question

If an air bubble rises from the bottom of a mercury tank to the top its volume become 112times. When normal pressure is 76 cm of Hg then the depth of the Hg tank is


A
38 cm
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B
132 cm
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C
76 cm
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D
49 cm
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Solution

The correct option is A 38 cm
let the height be h
pressure at the bottom = h + 76 (atmospheric pressure)
now as it reaches at the top, pressure = 76 (only atmospheric pressure now)
at constant temperature we can apply Boyle's law
here P1 = h + 76
P2 = 76
V2=32V1
so by Boyle's law, we get
P1V1=P2V2
on solving this gives h = 38 cm

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