Question

If an angle is $6^{\circ }$ less than twice its supplement, how much does each angle measure?

Answer 1

Let the angle be $x$

$\Rightarrow$ Supplement of $\left(x\right)=$ ${180}^{\circ }-x$

Then according to question,

$x=2\left({180}^{\circ }-x\right)-6^{\circ }$

$\Rightarrow x+6^{\circ }={360}^{\circ }-2x$

$\Rightarrow 3x={354}^{\circ }$

$\Rightarrow x={118}^{\circ }$

$\Rightarrow$ Supplement of $\left(x\right)=$ ${180}^{\circ }-{118}^{\circ }={62}^{\circ }$

Hence, the required angles are ${118}^{\circ }$ and ${62}^{\circ }$.