Question

If an average person jogs, he produces $14.5\times {10}^{4}cal/min$.This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming $1kg$ requires $580\times {10}^{3}cal$ for evaporation) is

• A. $0.25kg$
• B. $2.25kg$
• C. $0.20kg$
• D. $0.05kg$

Answer 1

The correct option is A $0.25kg$

Given: Calories produced per minute $=14.5\times {10}^{4}cal/min$⁡
Latent heat $=580\times {10}^{3}cal/kg$
Therefore,
Amount of sweat evaporated per minute $=\frac{Sweatproduces/minute}{Numberofcaloriesrequiredforevaporation/kg}$
$=\frac{Caloriesproduced\left(heatproduced\right)/minute}{Latentheat\left(incal/kg\right)}$
$=\frac{14.5\times {10}^4}{580\times {10}^3}=\frac{145}{580}=0.25kg$

Final Answer: (a).