If an electric iron of 1200 W is used for 30 minutes everyday, find electric energy consumed in the month of April.

18 kWh

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15 kWh

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60 kWh

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10 kWh

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Solution

The correct option is A 18 kWh
Given that,
Power $= 1200 W$ = $1.2 k W h$
Time $=$ 30 min / day $\times$ 30 days $= 0.5 h \times 30 =$ 15 h
Energy $= P o w e r \times T i m e = 1.2 \times 15 =$ $18 k W h$ .

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Question 20
If an electric iron of 1200 W is used for 30 minutes every day, find electric energy consumed in the month of April.

Question 20
If an electric iron of 1200 W is used for 30 minutes every day, find electric energy consumed in the month of April.

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