If an electron in a hydrogen atom (ground state) absorbs a photon of $12.1 e V$ , then change in angular momentum of electron is

h / 2 π

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h / 4 π

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3 h / 2 π

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h / π

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Solution

The correct option is D $h / π$
$L = \frac{n h}{2 π}$
$e^{-}$ excites from n = 1 to n = 3, $Δ L = L_{f} - L_{i}$
= $\frac{3 h}{2 π} - \frac{h}{2 π} = h / π$

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