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Question

If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength λ. When it jumps from the 4th orbit to the 3rd orbit, the corresponding wavelength of the photon will be


A
2013λ
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B
1625λ
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C
916λ
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D
207λ
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Solution

The correct option is C 207λ
Wavelength of emitted photon,       
1λ=R(1n221n21)
Transition from  n1=3  to  n2=2:
1λ=R(122132)=5R36_____(1)
Transition from  n1=4  to  n2=3
1λ=R(132142)=7R144 ____(2)
Dividing (1) by (2), we get     
λλ=5R/367R/144=207
λ=207λ 

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