Question

If an electron in $H-$atom jumps from one orbit to other its angular momentum doubles. If the new radius ${}^{\prime }{x}^{\prime }$ times the old radius, then find $x$?

Answer 1

We know that angular moment$=\frac{nh}{2\pi }$ given $l_1=\frac{nh}{2\pi }{l}_2=\frac{2nh}{2\pi }{n}_2=2n$

We know that $r\propto n^2{r}_1\propto n_1^2{r}_2\propto n_2^2$ $r=radius$

$\frac{r_2}{r_1}={\left(\frac{n_2}{n_1}\right)}^2$

$\frac{r_2}{r_1}=2^2⟹r_2=4r_1$ Hence, $x=4$